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The position vector of the point (1, 2, 0) is....Ai + j +kBi + 2j + kCi + 2jD2j + k

Question

The position vector of the point (1, 2, 0) is....Ai + j +kBi + 2j + kCi + 2jD2j + k
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Solution 1

To determine the position vector of the point (1, 2, 0), we need to express it in terms of the unit vectors i \mathbf{i} , j \mathbf{j} , and k \mathbf{k} . The coordinates of the point (1, 2, 0) correspond to the coefficients of these unit vectors.

Here's the step-by-step process:

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