The graphs of y = f(x) and y = 1/f(x) for 𝑓(𝑥)=18𝑥−32 have two invariant points: (a,b) and (c,d).State the value of (a+b+c+d
Question
Solution 1
Para encontrar los puntos invariantes de las gráficas de ( y = f(x) ) y ( y = \frac{1}{f(x)} ) para ( f(x) = 18x - 32 ), debemos resolver la ecuación ( f(x) = \frac{1}{f(x)} ).
Igualamos ( f(x) ) a ( \frac{1}{f(x)} ): [ 18x - 32 = \frac{1}{18x - 32} ]
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