0.19 mol of MnBr2 are dissolved in 1.18 L of water. What is the concentration of this solution in molarity?

1. Break Down the Problem

To find the molarity of a solution, we need to calculate the concentration in moles per liter (mol/L). The formula for molarity (M) is:

$\text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}}$

2. Relevant Concepts

• Moles of solute: 0.19 mol of MnBr2
• Volume of solution: 1.18 L

3. Analysis and Detail

We can directly substitute the known values into the molarity formula:

$\text{Molarity (M)} = \frac{0.19 \text{ mol}}{1.18 \text{ L}}$

4. Verify and Summarize

Now we perform the division to find the molarity:

$\text{Molarity (M)} \approx 0.161016 \text{ mol/L}$

Final Answer

The concentration of the MnBr2 solution is approximately 0.161 M.