Total number of mole of reactants involved in the reaction for the preparation of boric acid from tri halide of boron and water is
Question
Solution 1
The reaction for the preparation of boric acid from tri halide of boron and water is as follows:
BX3 + 3H2O → B(OH)3 + 3HX
Where BX3 is the tri halide of boron (Boron Trichloride, Boron Tribromide, etc.) and HX is a halogen acid (Hydrochloric acid, Hydrobromic acid, etc.)
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