What is the output of the following C code?char *ptr;char mystring[] = "abcdefg";ptr = myString;ptr += 5;a.fgb.efgc.defgd.bcdefg
Question
What is the output of the following C code?
char *ptr;
char mystring[] = "abcdefg";
ptr = myString;
ptr += 5;
Options:
- a. fg
- b. ef
- c. def
- d. bcdefg
Solution
Sure, here is the step-by-step explanation of the output of the given code:
- Declare a character pointer variable named "ptr".
- Declare a character array named "mystring" and initialize it with the string "abcdefg".
- Assign the address of the first element of "mystring" to the pointer variable "ptr".
- Increment the pointer "ptr" by 5 positions.
- The output will be the string starting from the 6th character of "mystring" onwards, which is "fgb.efgc.defgd.bcdefg".
Please note that the output may vary depending on the compiler and system you are using.
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