The sum of four consecutive integers is 1290.The greatest of them is?Options760220324NONE
Question
Solution 1
Vamos resolver o problema passo a passo.
Vamos chamar os quatro números inteiros consecutivos de ( n, n+1, n+2, n+3 ).
A soma desses quatro números é dada por: [ n + (n+1) + (n+2) + (n+3) = 1290 ]
Simplificando a equação: [ n + n + 1 + n + 2 + n + 3 = 1290 ] [ 4n + 6 = 1290 ]
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