What is the decreasing order of stability of the ions?I. CH3−C+H−CH3 II. CH3−C+H−OCH3III. CH3−C+H−COCH3
Question
What is the decreasing order of stability of the ions?
I. CH3−C^+H−CH3
II. CH3−C^+H−OCH3
III. CH3−C^+H−COCH3
Solution
The stability of carbocations is determined by the ability of the surrounding atoms or groups to donate electron density to the positively charged carbon. This is often referred to as +I effect or hyperconjugation.
The order of stability for the given carbocations can be determined as follows:
I. CH3−C+H−CH3: This is a secondary carbocation, where the positively charged carbon is surrounded by two methyl groups. These methyl groups can donate electron density to the positively charged carbon, stabilizing it.
II. CH3−C+H−OCH3: This is a secondary carbocation where one of the groups is a methoxy group (-OCH3). Oxygen is more electronegative than carbon, so it will not donate electron density as effectively as a carbon. However, it can still provide some stabilization through resonance.
III. CH3−C+H−COCH3: This is a secondary carbocation where one of the groups is a carbonyl group (-COCH3). The carbonyl group is electron withdrawing, which destabilizes the carbocation.
So, the order of stability is: I > II > III.
Similar Questions
What is the order of stability of the following carbocations ?(I) CH2=CH−C⊕H2I CH2=CH-C⊕H2 (II) CH3−C⊕H2;II CH3-C⊕H2; (III)III
Arrange the following carbanion in ascending order of stability.*1 pointI < II < IIIII < I < IIIII < III < IIII < II < I
Arrange following in decreasing order of C–H bond energy order ?A a > b > c > d B b > d > c > a C b > d > a > c D c > a > d > b
Based on MO theory, which of the following molecules and ions have the largest bondorder?A. H2 B. H2+C. He2 D. He2+
Arrange the following in increasing order of acidity with suitable explanation. ClCH 2 COOH, BrCH 2 COOH, ICH 2 COOH, FCH 2 COOH
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.