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If a haemophilic man marries a woman carrier for haemophilia, then the percentage of progeny that will be haemophilic would be25%50%75%100%

Question

If a haemophilic man marries a woman carrier for haemophilia, then the percentage of progeny that will be haemophilic would be

  • 25%
  • 50%
  • 75%
  • 100%
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Solution

Haemophilia is a sex-linked recessive disorder. This means that it is carried on the X chromosome.

A haemophilic man would have the genotype XhY (where h represents the haemophilia gene). A woman carrier for haemophilia would have the genotype XHXh (where H represents the normal gene and h represents the haemophilia gene).

Their possible offspring would have the following genotypes:

  1. XHXh (carrier female)
  2. XHY (normal male)
  3. XhXh (haemophilic female)
  4. XhY (haemophilic male)

So, 50% of their offspring (2 out of 4) would be haemophilic (one male and one female). Therefore, the correct answer is 50%.

This problem has been solved

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