What is the output of this C code?#include <stdio.h>void main(){double b = 3 % 0 * 1 - 4 / 2;printf("%lf", b);}-2Floating point Exception1None of the mentioned

Break Down the Problem

1. Identify the operation within the code: double b = 3 % 0 * 1 - 4 / 2;
2. Determine the behavior of the modulo operation when the divisor is zero.
3. Assess what the code prints based on the evaluation of the expression.

Relevant Concepts

1. Modulo (%) Operation: The modulo operation returns the remainder of a division. However, dividing by zero (in this case, 3 % 0) causes a runtime error in C.
2. Floating Point Exception: This is an error that can occur in C programs when invalid arithmetic operations are performed, such as division by zero.

Analysis and Detail

1. The expression 3 % 0 attempts to perform a modulo operation where the second operand is zero, which is undefined behavior in C.
2. Consequently, the program will not proceed further to compute * 1 - 4 / 2, nor will it produce a valid double value for b.
3. Instead, it ends with a runtime error leading to a floating-point exception.

Verify and Summarize

As per the analysis, the critical operation (3 % 0) leads to a runtime error, causing the program to terminate before it can print any output.

Final Answer

• The output of this C code will be: Floating point Exception.