A steady current is passing through a coil, magnitude of self- induced emf in it,will be:A. zero ⃝ B. maximum ⃝C. = LIt ⃝ D. = ILt
Question
Solution 1
The answer is A. Zero.
Here's why:
Self-induced emf in a coil is the emf induced in the coil due to its own changing magnetic field. This is given by Faraday's law of electromagnetic induction as ε = -L (dI/dt), where L is the inductance of the coil and dI/dt is the rate of change of current.
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