Define a quadratic function f(x)=(x+4.4)^2+1. What is the elasticity of f(x) at point x=1.3, rounded to 2 decimal places?
Question
Solution 1
To find the elasticity of the function f(x) at point x=1.3, we first need to find the derivative of the function, f'(x).
The derivative of f(x) = (x+4.4)^2 + 1 is f'(x) = 2*(x+4.4).
Next, we substitute x=1.3 into the derivative to find the rate of change of the function at that point.
f'(1.3) = Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
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