Determine Output :void show() { printf("PISTA "; show();}void main() { printf("CACHEW "); return 10;}
Question
Determine Output :
void show() {
printf("PISTA ");
show();
}
void main() {
printf("CACHEW ");
return 10;
}
Solution
The code you've provided seems to be written in C language. However, it contains a few errors and misconceptions. Here's a step-by-step analysis:
-
The
show()
function is a recursive function without a base case. This means it will call itself indefinitely, leading to a stack overflow error. -
The
main()
function is declared asvoid
, but you're trying to return an integer value10
. In C, themain()
function should be declared asint
if you want to return a value. -
The
printf("CACHEW ");
statement will print "CACHEW " to the console. -
The
show()
function is never called, so "PISTA " will never be printed. -
If you correct the
main()
function to return an integer and call theshow()
function, the program will print "CACHEW " once and then go into an infinite loop printing "PISTA ", eventually leading to a stack overflow error.
Here's a corrected version of your code:
#include <stdio.h>
void show() {
printf("PISTA ");
// show(); // Commented to prevent infinite recursion
}
int main() {
printf("CACHEW ");
show();
return 0;
}
This will print "CACHEW PISTA " to the console and then terminate successfully.
Similar Questions
what is the output of the given program?main(){#ifndef sanprintf("no");#endifprintf("yes");}
What will be the output of the following C code? #include void main() { m(); } void m() { printf("hi"); m(); }a.Compile time errorb.hic.Infinite hid.Nothing
What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}
What will be the output of the following C code?#include <stdio.h>int main() { int i; for (i = 0; i < 5; i++); printf("%d\n", i); return 0;}
What will be the output of the following program? #include<stdio.h> int main() { int i=10; if (i > 10) else printf ( "Hello Cocaine!" ); return 0; }
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.