7. Find the gradient for the function ๐ข = ๐(๐), ๐ = โ๐ฅ2 + ๐ฆ2 + ๐ง2.Answer: ๐๐ข = ๐โฒ(๐) ๐๐ .
Question
7. Find the gradient for the function
u = \phi(r), \quad r = \sqrt{x^2 + y^2 + z^2}.
Answer: \nabla u = \phi'(r) \mathbf{r}.
Solution
To find the gradient of the function u = ฯ(r), where r = โ(xยฒ + yยฒ + zยฒ), we need to use the chain rule for differentiation.
Step 1: Differentiate ฯ(r) with respect to r to get ฯโฒ(r).
Step 2: Differentiate r with respect to x, y, and z to get the vector (x/r, y/r, z/r). This is the unit vector in the direction of r, denoted as ๐๐.
Step 3: Multiply ฯโฒ(r) by ๐๐ to get the gradient of u, which is ๐๐ข = ฯโฒ(r) ๐๐.
So, the gradient of the function u = ฯ(r), where r = โ(xยฒ + yยฒ + zยฒ), is ๐๐ข = ฯโฒ(r) ๐๐.
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7. Find the gradient for the function ๐ข = ๐(๐), ๐ = โ๐ฅ2 + ๐ฆ2 + ๐ง2.Answer: ๐๐ข = ๐โฒ(๐) ๐๐ .
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