If the difference of squares of two consecutive numbers is 93, then determine the larger number. Ops: A. 45 B. 48 C. 47 D. 46
Question
Solution 1
Let's denote the two consecutive numbers as n and n+1.
The problem states that the difference of their squares is 93. This can be written as:
(n+1)^2 - n^2 = 93
Expanding and simplifying this equation gives:
n^2 + 2n + 1 - n^2 = 93
This simplifies to:
2n + 1 = 93
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